A random sample of 84 students at a university showed an average age of 22 years and a sample standard deviation of 3 years. Find the margin of error for the 94% confidence interval. (Assume that the population of students is large relative to the sample size. Round your solution to 4 decimal places)

The margin of error for the 94% confidence interval is 0.6154.

Step-by-step explanation:

The (1 - α)% confidence interval for population mean is:

The margin of error of this interval is:

The critical value of z for 94% confidence level is, z = 1.88.

Compute the margin of error for the 94% confidence interval as follows:

Thus, the margin of error for the 94% confidence interval is 0.6154.

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

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