Which of the following best completes the proof showing that ΔWXZ ~ ΔXYZ? triangles WXZ and XYZ that share side XZ with right angle XZW, WZ equals 10, XZ equals 5, and YZ equals 2 and one half

Since segment XZ is perpendicular to segment WY, angles WZX and XZY are both right angles and congruent. The proportion _ shows the corresponding sides are proportional, so the triangles are similar by the SAS Similarity Postulate.

5 over 10 equals 5 over 2 and one half

5 over 10 equals 5 over 5

10 over 5 equals 5 over 2 and one half

10 over 5 equals 2 and one half over 5

C. 10 over 5 equals 5 over 2 and one half

Step-by-step explanation:

The corresponding sides of ΔWXZ and ΔXYZ are:

WX and XY;

XZ and YZ;

WZ and XZ

If ΔWXZ ~ ΔXYZ, therefore the ratio of their corresponding sides will be the same.

That is:

Plug in the values of each given sides

Therefore, the proportion shows the corresponding sides are proportional. (2.5 = 2½).

✅The answer is:

C. 10 over 5 equals 5 over 2 and one half

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

the correct answer is $7.38

step-by-step explanation: