A snack bar at an outdoor fair is open from 10 A. M. To 5:30 P. M. And has 468 bottles of water for sale. Sales average 1.3 bottles of water per minute.

the question is incomplete, so I looked for similar ones

the number of bottles of water remaining as a function of time:

f(x) = -78x + 468

1.3 bottles are sold per minute x 60 minutes per hour = 78 bottles per hour

x = number of hours

the slope is -78

the y intercept is 468

domain = 0 ≤ x ≤ 7.5 hours (from 10 AM to 5:30 PM)

range = 0 ≤ y ≤ 468 bottles

the snack will run out of bottles of water by 4 PM

78x = 468

x = 468 / 78 = 6 hours

if the snack wants to have enough bottles of water to serve all its customers, it will need:

78 x 7.5 hours = 585 bottles of water

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°