Find x and the lengths of sides JM, MN, and JN. Triangle JMN is an isosceles triangle with side JM ≅ side MN. JM = 2x - 5, MN = 3x -9, and JN = x - 2.

x = 4

JM ≅ MN = 3

JN = 2

Step-by-step explanation:

In an isosceles triangle, two of the sides are equal. Given the lengths of sides of triangle JMN as JM, MN, and JN where JM ≅ MN

Given

JM = 2x - 5

MN = 3x -9, and

JN = x - 2.

Since JM≅ MN then;

2x - 5 = 3x-9

Collect like terms;

2x-3x = -9+5

-x = -4

multiply both sides ny -1;

-(-x) = -(-4)

x = 4

For side JM;

JM = 2x-5

JM = 2(4)-5

JM = 8-5

JM = 3

Since JM ≅ side MN, hence;

MN = 3

For side JN;

JN = x-2

JN = 4-2

JN = 2

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

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