F (x) = 3x^2 vertex axis x-int y-int max/min value domain range

F(x) = 3·x² vertex (0, 0) axis x = 0 x-int (0, 0) y-int (0, 0) min minimum  value (0, 0) domain (x ∈ R) range (f(x) ∈ R+)

Step-by-step explanation:

The given function is f(x) = 3·x²

The given parabola in vertex form y = a(x - h)² + k

Where;

(h, k) = The vertex

By comparison, we have;

h = 0

k - 0

Therefore;

1) The vertex = (0, 0)

2) The axis of symmetry = The line x = 0

3) The x-intercept = The vertex = (0, 0)

4) The y-intercept = The vertex = (0, 0)

5) The minimum value = The vertex = (0, 0)

6) The domain = All real numbers (x ∈ R)

7) The range = All positive real numbers including 0 (f(x) ∈ R+)

it has to be a.

2 2/3 hours duhh silly

step-by-step explanation: