How many liters each of a 45% acid solution and a 70% acid solution must be used to produce 50 liters of a 65% acid solution? (Round to two decimal places if necessary.)

The number of liters of the 45% acid solution = 10 liters

The number of liters of the 70% acid solution is = 40 liters

Step-by-step explanation:

How many liters each of a 45% acid solution and a 70% acid solution must be used to produce 50 liters of a 65% acid solution? (Round to two decimal places if necessary.)

Let x be the number of liters of the 45% acid solution

The number of liters of the 70% acid solution is y

x + y = 50

x = 50 - y

Also

How many liters each of a 45% acid solution and a 70% acid solution must be used to produce 50 liters of a 65% acid solution?

We have:

45% × x + 70% × y = 65% × 50

0.45x + 0.70y = 0.65 × 50

0.45x + 0.70y = 32.5

We substitute x = 50 - y in the equation

0.45(50 - y) + 0.70y = 32.5

= 22.5 - 0.45y + 0.70y = 32.5

= - 0.45y + 0.70y = 32.5 - 22.5

= 0.25y = 10

Divide both sides by 0.25

= y = 10/0.25

y = 40 liters

x = 50 - y

x = 50 - 40

x = 10 liters

Hence,

The number of liters of the 45% acid solution = 10 liters

The number of liters of the 70% acid solution is = 40 liters

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

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step-by-step explanation: