Esteban stands on a dock 1.25 yd above the water. A fish swims below Esteban at -4.61 yd from the surface of the water. How many yards apart are Esteban and the fish?

5.86yd

Step-by-step explanation:

From the question, we are informed that Esteban stands on a dock 1.25 yd above the water and that a fish swims below Esteban at -4.61 yd from the surface of the water.

The distance between Esteban and the fish can be calculated by subtracting -4.61 yd from 1.25 yd. This will be:

= 1.25 yd - (-4.61 yd)

= 1.25 yd + 4.61 yd

= 5.86 yd

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are