A die is rolled twice. Find the chance that the ace (single dot) comes up on one of the two rolls, but not both. Record your answer as a percentage rounded to the nearest tenth of a percent.

13.9%

Step-by-step explanation:

In order to calculate the probability of this happening, we would need to multiply the probability of one of the rolles being an ace with the probability of one of the roles NOT being an ace. Since the probability of rolling an ace is 1/6 (since there is only one ace in a six-sided die) then the probability of NOT rolling an ace is 5/6

or 0.1388     multiply by 100 to get percentage value

0.1388 * 100 = 13.9%

Therefore, the probability of getting one ace and one non-ace roll is 13.9%

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11