Three pumpkins are catapulted at a contest. How much farther does Pumpkin C travel than Pumpkin A? • Pumpkin A travels 0.61 mile. • Pumpkin B travels 0.28 mile farther than Pumpkin A. • Pumpkin B travels 0.06 mile farther than Pumpkin C.

0.22 miles

Step-by-step explanation:

Let

A = Distance pumpkin A travels = 0.61 miles

Distance pumpkin B travels is 0.28 mile farther than Pumpkin A

Distance pumpkin B travels is 0.06 miles further than pumpkin C

To calculate how much farther pumpkin C travels than pumpkin A we have the subtract their distances

So, pumpkin C traveled 0.22 miles more than pumpkin A.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: