You started a savings account with $125. Every month, you deposit $55 into your savings account. What is the linear equation that represents this relationship? y=55x−125y is equal to 55 x minus 125 y=125x+55y is equal to 125 x plus 55 y=55x+125y is equal to 55 x plus 125 y=125x−55

Step-by-step explanation:

Given Initial deposit = $125

If each moth $55 is being deposit, the balance each month will form an AP as shown;

125, 180, 235...

The nth term of the AP is expressed as;

y = a + (x-1)d

a is the first term = 125

d is the common difference = 180- 125 = 235-180 = 55

Substitute

y = 125 + (x-1)55

y =125+55x-55

y = 70+55x

y = 55x + 70

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

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step-by-step explanation: