The length of a square is increased by a 5th so that its new area is 44 cm2 more than the original value. find the difference in perimeter of two shapes.

Let the original length be x, then the new length is 6/5x
x^2 + 44 = (6/5 x)^2
x^2 + 44 = 36/25 x^2
36/25 x^2 - x^2 = 44
11/25 x^2 = 44
x^2 = (44 x 25)/11 = 100
x = 10 cm.
Therefore, original length is 10cm and new length is 1.2 x 10 = 12 cm.

Perimeter of a square = 4l
Therefore, difference in perimeter = 4(12) - 4(10) = 48 - 40 = 8 cm.

Bis the right answer