two buses x and y are moving towards each other on a straight east west main road. at a particular instant, another bus z on a road is 50km south of the main road and the bearing of X ,Yand z are 330⁰ and 360⁰ respectively. find the distance between X andY

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²

none of the above chief keef

< 4 = < 5 they are vertical angles

120 degrees

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