2/5 of two numbers is 56.One of the numbers is 36.What is the other number?

104

Step-by-step explanation:

Let x = the unknown second number.  2/5 of [the sum of] two numbers is 56. One of the numbers is 36:

(2/5)(36+x) = 56

Multiply both sides by 5/2:

36 + x = 56*5/2

36 + x = 140

x = 104

Check:

(2/5)(36+104)=56

(2/5)(140)=556

280/5 = 56

56 = 56

Check!

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)