K+a=500 3k+10a=3600

K+a=500
K= 500-a

Using substitution, what would i do for this next part?

3K+10(500-a) = 3600

What is the solution for the following system of equations? use any method to solve. 2x + 8y = 4 x = -3y + 5 question 4 options: x = 14, y= -3 x = 2, y = -3 x = -3, y = -3 x = 12, y = 5