Mathematics, 10.11.2020 22:00 teresaduggan1433

K+a=500 3k+10a=3600

K+a=500
K= 500-a

Using substitution, what would i do for this next part?

3K+10(500-a) = 3600

Answers: 2

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K+a=500 3k+10a=3600

K+a=500
K= 500-a

Using substitution, what would i...