Which point would map onto itself after a reflection across the line y = -x? (-4, -4)
(-4, 0)
(0, -4)
(4, -4)

The required point is (4, -4)

Step-by-step explanation:

For any point to map onto itself after reflection across the line, The first condition is that the point must lie on the line.

So, check the given points which lie on the equation of the given line :

y = -x

(-4, -4)

y = -4 and -x = - (-4) = 4

⇒ y ≠ -x

So, (-4, -4) is rejected.

(-4, 0)

y = -4 and -x = 0

⇒ y ≠ -x

So, (-4, 0) is rejected.

(0, -4)

y = 0 and -x = - (-4) = 4

⇒ y ≠ -x

So, (0, -4) is rejected.

(4, -4)

y = 4 and -x = - (-4) = 4

⇒ y = -x

So, (4, -4) is the required point which would map onto itself after a reflection across the given line y = -x

Hence, the required point is (4, -4)

step-by-step explanation:

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solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.