Two water tanks are being filled. The water in Tank A is 3 inches deep, and the depth of the water increases 4 inches every hour. The water in Tank B is 10 inches deep, and the depth is increasing by 2 inches every hour.
Write an inequality to determine when the water in Tank A will be deeper than the water in Tank B.

Define the variable:

Write the inequality:

variable: number of hours

inequality (unsimplified): 4x+3 > 2x+10

inequality (simplified): x > 3.5

at least 4 hours

Step-by-step explanation:

we can use mx+b to solve this. m will be the rate at which the water level rises and b will be your stating point. x defines the hour; this is your varible as it can change

Tank A: 4x+3

Tank B: 2x+10

since we want to find when tank a will have be deeper than tank b, we set the inequality to solve for greater than tank a: 4x+3 > 2x+10

subtract 3 to both sides: 4x > 2x + 7

subtract 2x to both sides: 2x > 7

divide both sides by 2: x > 3.5

step-by-step explanation:

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.