What is the length of the radius of a circle with center (10, -14) that is tangent to the line x=13?

The length of the radius of a circle as described in the question is; 14.32

The center of the circle is at; (10, -14)

The line that is tangent to the circle is; x = 13.

The coordinate of a point on the line is therefore; (13, 0)

The length of the radius of the circle can.be obtained from Pythagoras theorem as;

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length of radius of a circle = 3

Step-by-step explanation:

a tangent line touches the circle at one point

if the tangent line is at x=13 (vertical line) and the center of the circle is

(x,y) = (10,-14) with its center x at 10; then take the difference to find the radius;

x(tangent line) - x(center of circle) = radius of circle

length of radius of a circle = 13-10 = 3

you can also graph the circle and draw the tangent line to find the radius

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

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step-by-step explanation: