What is the equation of a line, in point-slope form, that passes through (-8, 1) and has a slope of 5/6?

y-1=(x+8)

Step-by-step explanation:

1. y-y1=m(x-x1) (point slope form)

2. y1 is the y of your given point and x1 is the x of your given point

3. m is the slope

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

the answer is b