A 5.1-ft-tall person walks away from a 12-ft lamppost at a constant rate of 3.9 ft/sec. What is the rate that the tip of the person's shadow moves away from the lamppost when the person is 9 ft away from the lampost?

6.78ft/sec

Step-by-step explanation:

From the question, dx/dt= 3.9 ft/sec

We are looking for Dy/dt

From geometry,vof this case the relationship between x and y is needed here, there is two similar triangle that exhibited by the man and the lamb

12/y= 5.1/(y-x)

Then ,cross multiply, we have

12(y-x)=5.1y

12y-12x=5.1y

12y-5.1y=12x

6.9y=12x

y=( 12/6.9)x

Differentiating implicitly the bother sides with respect to t, we have

Dy/dt= ( 12/6.9)dx/dt

But dx/dt= 3.9 ft/sec

Then Dy/dt= ( 12/6.9)× 3.9

Dy/dt=6.78ft/sec

Hence, the rate that the tip of the person's shadow moves away from the lamppost when the person is 9 ft away from the lampost is 6.78ft/sec

CHECK THE ATTACHMENT FOR THE FIQURE

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!