Approximately 1 in 28 people of Ashkenazi Jewish descent are Tay-Sachs carriers. In randomly sampling one man and one woman from this population, what is the probability neither is a Tay-Sachs carrier? What is the probability both are carriers?

a) probability that neither is Tay-Sachs carrier is 0.9298

b) the probability that both are carriers is 0.001276

Step-by-step explanation:

Given that;

1 in 28 people of Ashkenazi jewish descent are Tay-Sachs carrier.

so P(Carrier) = 1/28 =

also P( Not a carrier) = 1 - 1/28 = 0.9643

Now After Sampling 1 man and 1 woman from the population;

a)

the probability neither is Tay-Sachs carrier

P( Neither is a Carrier) = 27/28 × 27/28 = 0.9298

Therefore probability that neither is Tay-Sachs carrier is 0.9298

b)

the probability both are carriers

P( Both are Carriers) = 1/28 × 1/28 = 0.001276

Therefore the probability that both are carriers is 0.001276

d

step-by-step explanation:

hello and welcome!

so, when we see the words "proportional" along with a table, we need to know that we're looking numbers that divide by the same thing.

looking at this table, we simply have to do a trial and error, and divide to see which numbers have the same quotient. if you look at choice a & c, they both have equal quotients for three of the numbers, with one exception, so those can't be the answer. looking at b, there is no similarity, so that can't be it. then, we see d; if you divide all the numbers in the table, you'll see that they all divide by two, which is a proportional relationship, and our answer!

also, always remember that the x will always be the number that goes into y, and somewhere behind this table, is a formula. for this specific table, the formula would be:

since our x-value is being divided by two to get the y-value. and if they were to ask for more numbers in the series, this is the formula you would use to find them.