>I'm sorry but how do I do this? Solving the equation of the form a cos 0 + b sin 0 = c

Question;
Solve the equation 4 sin 20 - 3 cos 20 = 3, for 0° ses 360°

θ = 36.9°, 90°, 216.9°, or 270°

Step-by-step explanation:

4 sin 2θ − 3 cos 2θ = 3

Use double angle formulas:

4 (2 sin θ cos θ) − 3 (cos²θ − sin²θ) = 3

8 sin θ cos θ − 3 cos²θ + 3 sin²θ = 3

Use Pythagorean identity:

8 sin θ cos θ − 3 cos²θ + 3 sin²θ = 3 (sin²θ + cos²θ)

8 sin θ cos θ − 3 cos²θ + 3 sin²θ = 3 sin²θ + 3 cos²θ

8 sin θ cos θ − 6 cos²θ = 0

2 cos θ (4 sin θ − 3 cos θ) = 0

2 cos θ = 0

θ = 90° or 270°

4 sin θ − 3 cos θ = 0

4 sin θ = 3 cos θ

tan θ = 3/4

θ = 36.9° or 216.9°

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.