Given f(x) = 2x^3 + ax^2 - 7a^2x - 6a^3, determine whether or not x-a and x+a are factors of f(x). Hence, find, in terms of a, the roots of f(x) = 0. thankyou so much

Step-by-step explanation:

f(x) = 2x³ + ax² - 7a²x - 6a³

= 2x³ - 2a²x + ax² - a³ - 5a²x - 5a³

= 2x(x² - a²) + a(x² - a²) - 5a²(x+a)

= (2x+a)(x - a)(x + a) - 5a²(x + a)

= (x + a)[(2x + a)(x - a) - 5a²]

= (x + a)(2x² - ax - 6a²)

= (x + a)(2x + 3a)(x - 2a)

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s