Consider the line y=5x -3 Find the equation of the line that is patellar to this line and passes through the point (-8, -3) Consider the line y=5x -3

The equation of the line that is parallel to given line and passes through the point (-8, -3) is:

Step-by-step explanation:

Given equation of line is:

The general form of equation of line in slope-intercept form is written as:

Here m(co-efficient of x) is the slope of the line and b is the y-intercept.

Comparing the given equation with the general form we get

m = 5

Two parallel lines have same slope so the slope of any line parallel to given line will also be 5.

Let m1 be the slope of required line parallel to y=5x-3

Then m1=5

Putting in general form

To find the value of b(y-intercept) the given point has to be put in the equation from which the line passes.

The point is (-8,-3)

Putting the value of b and m1, we get

Hence,

The equation of the line that is parallel to given line and passes through the point (-8, -3) is:

where's the diagrams?

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: