PLEASE HELP WILL MARK BRAINLIEST FOR GOOD AND CORRECT ANSWERS :)

Try to solve the following quadratic equations using the factoring method. If it doesn't work, use the quadratic formula. Sketch the parabola.

1) y = x^2 + 3x + 1

2) y = x^2 + 4x - 8

3) y= x^2 - 5x - 12

Step-by-step explanation:

1) x² + 3x + 1 = 0

a = 1    b = 3     c = 1

=> Δ = b² - 4ac = 9 - 4.1.1 = 5 > 0

so the quadratic equation have 2 solutions

=> x =

or  x =

2) x² + 4x - 8 = 0

a = 1    b' = 2    c = -8

Δ' = b'² - ac = 4 - 1.(-8) = 12 > 0

so the quadratic equation have 2 solutions

=> x =

or x =

3) x² - 5x -12 = 0

a = 1       b = -5    c = -12

Δ = b² - 4ac = 25 - 4.1.(-12) = 25 + 48 = 73 > 0

so the quadratic equation have 2 solutions

=> x =

or x =

answer by yourhope:

hi! : )

a farmer that lived in ancient egypt would most likely be barried in the sand, in the desert!

: )