write the point slope form of the line that passes through -8, 2 and is perpendicular to the line with a slope of negative 8

y = -1/8x + 1

Step-by-step explanation:

Line perpendicular to 8 is -1/8

If the line were to start at the origin, then y- intercept would be 0, and it would pass through the point (-8, 1) To pass through point (-8, 2), add 1 to y in the first example.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option