PLEASE HELP NEED ASAP

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

hi there!

1. define: accuracy

a) how close a measured value is to the actual (true) value.

hope this : )

im not sure what your asking ?

step-by-step explanation:

1st, 348.600

2nd, 256.905

3rd, 892.500

4th, 6937

last one stays the same since it has no decimal

step-by-step explanation: