Jill has a jar full of dimes and quarters. If she has a total of $27.20 and the number of quarters is less than twice the dimes, how many of each coin are in the jar?

She has 76 dimes and 78 quarters.

Step-by-step explanation:

Given data:

Total = $27.20

Solution:

Q = d + 2

Each quarter is 25 cents, or 0.25 of a dollar = 0.25q

Each dime is 10 cents = 0.10d

0.25q+0.10d = $27.20

Where q = d-2

Substitute in this equation:

0.25(d+2)+0.10d = 27.20

0.25d + 0.5 + 0.10d = 27.20

0.35d = 26.7

Divide both sides by 0.35

d = 76

She has 76 dimes and 76 + 2 = 78 quarters.

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61