The temperature one cold morning is -5 °C. By noon, the temperature had increased by 3 degrees and at 4 PM the temperature was zero. The increase from noon to 4 PM was

2°C

Step-by-step explanation:

Morning

-5°C

Noon (+3)

-2°C

4pm (+?)

0°C

Equation I used:

(-5) + (3) + x = 0

I'm assuming you're being taught how to work with negative intervals in algebra? Don't worry, that's why you're practising with temperature. Instead of asking online, try using the progress your teacher taught you. If you have notes, look back at them. Practise makes perfect :)

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb