Flying against the wind, a jet travels 1710 miles in 3 hours. Flying with the wind, the same jet travels 3720 miles in 4 hours. What is the rate of the jet in still air and what is the rate of the wind?

Rate of jet in still air = 750 mph

Rate of wind = 180 mph

Step-by-step explanation:

Let the rate of jet in still air = mph

Let the rate of air = mph

So, Rate of jet against the wind = mph

Rate of jet with the wind = mph

Formula for Speed/Rate is given as:

Distance traveled in 3 hours against the wind = 1710 miles

Distance traveled in 4 hours against the wind = 3720 miles

Adding (1) and (2):

By equation (1):

Rate of jet in still air = 750 mph

Rate of wind = 180 mph

idk

step-by-step explanation:

maybe try   if it is work from a book, if not try

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2