Is each pair equivalent or not ?

1 and 3 are true.

Step-by-step explanation:

For the first equation, you would add 2x to each side to result in the second equation.

For the third equation, you would divide by x on both sides, resulting in the second equation.

2. is not correct because the 3 is gone, and was "divided" from (x-4), but not the 15.

4. is not correct because of the extra x that is included in the second equation. That x makes the equations False.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.