Suppose the scores of students on an exam are normally distributed with a mean of 347 and a standard deviation of 38. Then approximately 95% of the exam scores lie between the integers

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

true. i hope this ! go answer some of my newest

10 - 8 = -2

  8 - 6 = -2

etc, so -2 is the common difference

step-by-step explanation: