Peggy decided to sell brownies and cookies to raise money for her basketball uniform. She sold
brownies for $3.00 and cookies for $2.50. If she
sold 3 fewer cookies than brownies and collected
$218 in all, then how many brownies did she sell?
Write and solve an equation (or a system of
equations) to find your solution.

Peggy sold 41 brownies.

Step-by-step explanation:

She sold three more brownies. 1 brownie cost $3.00, so 3 brownies cost $9.00 because 3×$3.00.

$218-$9 = $209

Figure out the cost of 1 cookie and 1 brownie: $3.00+$2.50=$5.50

$209÷$5.50=38

This means that Peggy sold 38 cookies.

Since she sold 3 more brownies than cookies, add 3 to 38.

3+38=41

So, Peggy sold 41 brownies.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.