What is the equation of the circle with center (-3,1) that passes through the point (-5, 3)? A)
(x - 3)2 + (y + 1)2 = 8
B)
(x + 3)2 + (y – 1)2 = 8
0)
(x + 1)2 – (y - 3)2 = 8
D)
(x + 3)2 - () - 1)2 = 8

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

Step-by-step explanation:

The equation of a circle with center (h,k) and radius r is given by:

Given

Center = (h,k) = (-3,1)

=> h = -3

=> k = 1

The distance between the center of circle and the point through which the circle passes will be the radius.

The distance formula is given by:

Given

Putting the values in the formula

Putting the values of h,k and r in general form of equation

Hence,

Option B) (x + 3)^2 + (y – 1)^2 = 8 is the correct answer.

it is c, trust i got your back lol

step-by-step explanation: