Bangs disease in Cattle can be a serious problem that if untreated could lead to sterility. On a ranch in Texas there were 400 cows put on two different diet plans (A and B) in order to prevent a Cow from contracting Bangs disease. Plan A is the treatment and Plan B is the control. The control group receives a standard diet and the treatment group receives a liquid steroid in their diet. The study is conduced for one year. The following table has the results Diet plan A Diet plan B Bangs 10 50 No Bangs 190 150 What are the estimated odds for getting Bangs disease on diet plan A?

Part (A) 16 cattle should be put on each diet in order to achieve a sufficiently small standard error.

Part (B) No, the required number of cattle should not double.

Step-by-step explanation:

Consider the provided information.

The standard error of the mean for each diet should not exceed 5kg.

Therefore, sample mean is =  

Part (A)

The population standard deviation of weight gain is guessed to be about 20kg on any of the diets,

From the above  

It is given that  

As we know  

Thus,

16 cattle should be put on each diet in order to achieve a sufficiently small standard error.

Part (B) If the guess of the s.d is doubled, to 40kg, does the required number of cattle double?

From the above  

It is given that  

Thus,

64 cattle are required, which is not the double of 16.

Hence, No, the required number of cattle should not double.

answer: howdy

step-by-step explanation:

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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