Which of the following relations has a range of {-8, -6, 4}? A. {(-8,2), (-6,2), (4,2)}
B. {(-8,2), (-6,4), (2,4)}
C. {(1, -8), (4, -6), (1, -6) (4, -4)}
D. {(1, -8), (4, -6), (1, -6) (5,4)}

D. {(1, -8), (4, -6), (1, -6) (5,4)}

Step-by-step explanation:

The Range of a Relation

Is the set of all second elements of ordered pairs (y-coordinates). Only the elements used by the relation or function constitute the range.

For example, for the ordered pair of a relation (5,2), 5 belongs to the domain and 2 belongs to the range.

Given the range {-8,-6,4} we only have to go through the options and check which one has these values as the second element of the ordered pairs.

Note option D has y-coordinates -8, -6, -6, and 4. Those values correspond to the given range, thus the answer is

D. {(1, -8), (4, -6), (1, -6) (5,4)}

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval