Write the equation of a line that has a slope of 3 and goes through the point (2, 1).

Help?

y = 3x - 5

Step-by-step explanation:

You use the equation y = mx + b, and you plug in what you know. The slope is already 3 so you do y = 3x + b

after that, you plug in y and x, because (2,1) are the values of x and y.

1 = 3(2) + b

1 = 6 + b

subtract 6 from both sides to isolate the b

-5 = b

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2