charlotte is playing a beanbag toss game. she has a 10% chance of hitting the 3- point hole, a 30% chance of hitting the 1- point hole, and a 60% chance of getting 0 points. how many bean bags should we expect to toss to get 12 points? describe how you will use a random number table to conduct this simulation

The number of bean bags that we should expect her to toss to get 12 points is 20 bean bags.

Based on the information given, the expected value of the toss will be:

= 10%(3) + 30%(1) + 60%(0)

= 0.10(3) + 0.30(1) + 0.60(0)

= 0.30 + 0.30 + 0

= 0.60

Therefore, the expected number of tosses needed will be:

= 12/0.60

= 20

Therefore, the number of bean bags that we should expect her to toss to get 12 points is 20 bean bags.

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20

Step-by-step explanation:

The expected value of a toss is:

E(X) = (0.10) (3) + (0.30) (1) + (0.60) (0)

E(X) = 0.6

If she scores an average of 0.6 points per toss, then the expected number of tosses needed to get 12 points is:

12 / 0.6 = 20

Using a random number table, we can assign digit 0 as a 3-point hole, digits 1-3 as a 1-point hole, and digits 4-9 as no points.  Read the digits and add the points until you get 12 points.  The number of digits read is the number of beanbag tosses.