Error Analysis A classmate solves the equation 8 + 2(8r - 2r) = 4(3r + 2).
She says r = 0 is the only solution. Is
she correct? Explain.

Please need your help

Yes, the student is correct, r is equal to 0.

Step-by-step explanation:

This equation can be checked by plugging 0 in for each r in the equation.

So we take, 8+2(8r-2r)=4(3r+2) and apply 0 to the r's. Which results in:

8+2(8(0)-2(0))=4(3(0)+2)) Using pemdas, we know to work within the parenthesis first. 8*0 is equal to 0, and 2*0 is equal to 0. Now we have 8+2(0-0)=4(3(0)+2)). 0 minus 0 is 0. 8+2(0)=4(3(0)+2)) Next, we can work within the parenthesis on the right side of the equation. Therefore, 3*0 is 0, and 0 plus 2 equals 2. Now our equation looks like 8+2(0)=4(2). Next we check for exponents (pEmdas), and find none so we can move onto multiplication (peMdas). We can multiply 2*0 to get 0, and 4*2, which equals 8. Our equation now looks like 8+0=8. Moving on to division (pemDas), which is not present, leads us to addition(pemdAs). 8 plus 0 equal 8, meaning our final equation is 8=8. meaning the student is correct and r=0.

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step-by-step explanation:

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