Doris is playing a game. She rolls three six-sided number cubes to tell her how many squares to move. If two number cubes show 4 and 3, how many different possible numbers of squares may she move on her turn?

6 possible values of squares that she can move.

Step-by-step explanation:

In these events, as given

Doris

- rolls 3 standard dice(s) (or is it die, dies?))

- two of them land on 4 and 3

-Find how many possible squares can she move

So, it is already known that Doris has to move 7 squares (because 3 + 4 = 7), yet she has another 6 sets of possibilities because a dice has 6 facets.

Hence she has 6 different possible numbers of squares she can move.

The possibilities are:

-8 squares (if she rolls a 1)

-9 squares (if she rolls a 2)

-10 squares (if she rolls a 3)

-11 squares (if she rolls a 4)

-12 squares (if she rolls a 5)

-13 squares (if she rolls a 6)