In the diagram, PQR is a straight line. Find the value of X.

PLEASE HELP

In the above figure ,

∠QOR=2×∠QMR=100

0

(1) (Angle made by chord on the major segment is half of angle made by it on centre .)

In △QOR,OQ=OR→∠OQR=∠ORQ(2)

Using (1) , (2) and angle sum property of triangle in △QOR

∠OQR=∠ORQ=40

0

(3)

Now ∠MQP is the exterior angle of △MQR

So, ∠MQP=50

0

+40

0

+40

0

=130

0

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.