A ball is thrown into the air with a initial velocity of 25 meters per second. The function h(t)+-4.9t^2+25t+6 represents the height of the t in seconds. Ball above the ground in meters, with respect to time. What would be a reasonable domain for 36.9 meters

[2.1, 3]

Step-by-step explanation:

Given the height of the ball modelled by the equation;

h(t) =-4.9t^2+25t+6

Required

Domain for 36.9m

To get that we are to find the value of the input variable which is the time t  when h(t) = 36.9

Substitute

36.9 = -4.9t^2+25t+6

multiply through by -10

-369 = 49t²-250t-60

49t²-250t-60 + 369 = 0

49t²-250t+309 = 0

Find the domain of t

49t²-147t-103t+309 = 0

49t(t-3)-103(t-3) = 0

(49t-103)(t-3) = 0

49t - 103 = 0 and t-3 = 0

49t = 103 and t = 3

t = 103/49 and t = 3

t = 2.1 and t = 3

Hence the reasonable domain for 36.9m is [2.1, 3]

the graph is negative for all real values of x where   -6 < x < -2.

step-by-step explanation:

this refers to the values of f(x) in the area below the x-axis.

answer:   he will receive $21093.75 only.

explanation:

since we have given that

cost of house = $180,000

since he has a coinsurance clause of 75%,i.e. he does not fully insured his property.

amount the owner insured for the property = $101,250.

amount he lost in damage = $50,000

amount he will receive from insurance is given by

so, he will receive $21093.75 only.