A soccer team ordered 12 jerseys and 12 pairs of shorts, for a total of $156. Later, they had to order 4 more jerseys and 6 more pairs of shorts, for a total of $62. The system of equations that can be used to find x, the cost of each jersey, and y, the cost of each pair of shorts is shown. 12x + 12y = 156 4x + 6y = 62 What is the cost of each jersey? $5 $8 $12 $13

The cost of each jersey given the equation is $8

Given equation:

12x + 12y = 156 (1)

4x + 6y = 62 (2)

multiply (2) by 2 to eliminate y

8x + 12y = 124 (3)

12x + 12y = 156 (1)

Subtract (3) from (1)

4x = 32

x = 32/4

x = $8

Learn more about equation:

link

Cost of each jersey = $8

Step-by-step explanation:

Given:

Cost of each jersey = x

Cost of each shorts = y

12x + 12y = 156

4x + 6y = 62

Find:

Cost of each jersey

Computation:

12x + 12y = 156

Divide 12 in whole equation

x + y = 13

y = 13 - x

4x + 6y = 62

4x + 6(13 - x) = 62

4x + 78 - 6x = 62

-2x = -16

x = 8

Cost of each jersey = $8

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47