A trailer will be used to transport several 40-pound crates to a store. The greatest amount of weight that can be loaded into the trailer is 1,050 pounds. An 82-pound crate has already been loaded onto the trailer. What is the greatest number of 40-pound crates that can be loaded onto the trailer?

Given :

A trailer will be used to transport several 40-pound crates to a store.

The greatest amount of weight that can be loaded into the trailer is 1,050 pounds.

An 82-pound crate has already been loaded onto the trailer.

To Find :

The greatest number of 40-pound crates that can be loaded onto the trailer.

Solution :

Weight left = 1050 - 80 = 970 pound.

Let, number of 40 pounds crates that can be loaded are x.

Since, crate cannot be in fraction, so maximum crate that can be loaded is 24.

Hence, this is the required solution.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

positive

step-by-step explanation:

the quadrant is facing upwards