League baseball team plays 122 games in a season. If the team won 14 more than three times as many games as they lost, how many wins and losses did the team have?

Given:

Total number of games in a season = 122

The team won 14 more than three times as many games as they lost.

To find:

The number of wins and losses.

Solution:

Let the number of losses be x.

Then, according to the question

Number of wins = 3x+14

We know that,

Win + losses = Total number of games

Subtract 14 from both sides.

Divide both sides by 4.

Now,

Number of losses = 27

Number of wins

Therefore, the team won 95 games and they lost 27 games.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x