A motel rents double rooms at $34 per day and single rooms at $27 per day. If 26 rooms were rented one day for a total of $807, how many rooms of each kind were rented? system of equations

Let, number of double rooms and single rooms are d and s.

d + s = 26     1 )

Hotel rents double rooms at $34 per day and single rooms at $27 per day.

34d + 27s = 807   2)

Solving equation 1 and 2, we get :

34( 26 - s ) + 27s = 807

884 - 34s + 27s = 807

7s = 77

s = 11

And d = 26 - 11 = 15

Therefore, number of double rooms and single rooms are 15 and 11.

Hence, this is the required solution.

depends on how many days you are talking about

step-by-step explanation: