Question 3 of 3 Will wanted to solve the problem
468
÷
12
using partial quotients.

Which of the methods could be used to find the quotient? Select all that apply.

A.
Subtract (
10
×
12
) from 468 to get 348. Subtract (
3
×
12
) from 348 to get 312. Subtract (
9
×
12
) from 292.

B.
Subtract (
30
×
12
) from 468 to get 108. Subtract (
9
×
12
) from 108.

C.
Subtract (
20
×
12
) from 468 to get 228. Subtract (
10
×
12
) from 228 to get 108. Subtract (
3
×
12
) from 108 to get 72. Subtract (
6
×
12
) from 72.

D.
Subtract (
30
×
12
) from 468 to get 108. Subtract (
4
×
12
) from 108 to get 60. Subtract (
4
×
12
) from 60.

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

answer: 0,6

step-by-step explanation:

this would make it the y intercept.

agree

step-by-step explanation: