Find three consecutive odd integers such that their sum decreased by the second equals 50.

23, 25, and 27.

Step-by-step explanation:

Let's start by defining a variable.  Let x be the first of the three odd numbers.  Since odd numbers are 2 apart, that means that the other two numbers are x + 2 and x + 4.

Now, their sum is x + (x + 2) + (x + 4) which equals 3x + 6.

Decrease that by the second number, x + 2.  That means:  3x + 6 - (x + 2), which is equal to 2x + 4.

So now we know that 2x + 4 = 50, and we can solve that easily:

2x + 4 = 50

2x = 46

x = 23

Therefore, the three odd numbers are 23, 25, and 27.

idn

step-by-step explanation:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation