Tyler bought 3 calculators and 7 pens for $67.80. Barbra bought 6 calculators and 2 pens for $92.40. How much does each pen cost?

Each pen costs $3.60 (Each calculator costs $14.20).

Step-by-step explanation:

Let c represent calculator

Let p represent pen

3c + 7p = 67.8

6c + 2p = 92.4

Step 1: Solve 3c + 7p = 67.8 for c:

3c + 7p = 67.8

3c + 7p + −7p = 67.8 + −7p (Add -7p to both sides)

3c = −7p + 67.8

3c/3 = −7p + 67.8/3 (Divide both sides by 3)

c = −7/3p + 22.6

Step 2: Substitute −7/3p + 22.6 for c in 6c + 2p = 92.4:

6c+2p=92.4

6(−7/3p + 22.6) + 2p = 92.4

−12p + 135.6 = 92.4 (Simplify both sides of the equation)

−12p + 135.6 + −135.6 = 92.4 + −135.6 (Add -135.6 to both sides)

−12p = −43.2

−12p/−12 = −43.2/−12 (Divide both sides by -12)

p = 3.6

Step 3: Substitute 3.6 for p in c = −7/3p + 22.6:

c = −7/3p + 22.6

c= −7/3(3.6) + 22.6

c = 14.2 (Simplify both sides of the equation)

c = 14.2 and p = 3.6

Hope this helps and have a great day :)

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mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says