The function f(x) has an average rate of change on the interval -2≤x≤3 of 17/5. If f(-2)=9 then which of the following is the value of f(3)? (1)12.4
(2)17
(3)21.8
(4)26

f(3) = 26

Step-by-step explanation:

Average rate of change of a function on an interval is;

f(a) - f(b)/(a-b)

Here, we want to find the value of f(-3)

To find the average rate of change on the given interval;

we have;

f(3) - f(-2)/3-(-2) = 17/5

f(3)-9/5 = 17/5

Since denominator is same, we equate numerator;

f(3)-9 = 17

f(3) = 17 + 9

f(3) = 26

a

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752