The length of a rectangle is 4 inches more than its width. If 2 inches are taken from the length and added to the width, the figure becomes a square with an area of 272.25 sq inches. If the width of the rectangle is x, what is the length of the rectangle in terms of x?

L = W+4 (the length is 4 inches more than length (given))

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L-2 (if 2 inches are taken from L) and added to the width (W+2) the figure becomes a square.

A square has 4 equal sides.

L-2 = W+2

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We are told the area of the square is 272.25.

(L-2)(X+2) = 272.25

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Substituting from L = W+4

(l+4 -2)(w+ 2) = 272.25

(w+2)(w+2) = 272.25

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Taking the square root

(W+2) = sqrt(272.25) = 16.5

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Subtracting 2 from both sides

W = 12

and

L = W+4 = 16

.

Is the length 4 more than width? Yes.

If you subtract 2 from length and add 2 to width, and then multiply them, is the result 272.25? Yes.

Done. kindlyrecheck=)

sry if something's wrong ^_^

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions